Recent content by Sailaway

Sorry the Poisson's equation forms \nabla \circ (\sigma \nabla (V - V^{p})) = 0 \nabla \circ (\sigma (E - E^{p})) = 0

Hello guru's, I've been trying to figure out a way to incorporate an electric field source in the Helmholtz equation, and have been accumulating lots of question marks in my head. So in case of no static charge, \nabla^{2} E - \mu (\epsilon\frac{d^{2}}{dt^{2}} + \sigma\frac{d}{dt}) E = 0...