Recent content by salqmander

yes, i solved for horizontal position not vertical position

is it static friction

oh its sin not cos

78N back to the person

is this right? xf = xi + (vx)i delta t, xi=0 t = xf / vxi t = 25m / 19m/s, t = 1.3 seconds vyi = vi sin theta, vyi = 9.5m/s yf = yi + vyi delta t- 1/2g t ^2 = 0m + 9.5m/s(1.5) - 0.5(9.8m/s^2)(1.5)^2 yf = 3.2m 3.2-2.5 = +0.7m

should I use the equation xf = xi + (vx)i delta t for time and then yf = yi + vyi delta t- 1/2g t ^2

oh that makes sense. is it just contact force?

to the person, i believe there is friction force from the block,

yes i realized that g shouldn't be in a horizontal question, let me see

do you know how to solve part b? i'm not sure what to do my textbook is not very clear

yea i'm not sure

I think because the surface is ice friction is negligible, right?

There was a force of friction which is negligible because the ice is not slippery so are there no more forces acting on the ice? will it continue at a speed of 4m/s so 0 acceleration?

thank you is part b correct?

👍