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samalkhaiat's latest activity
samalkhaiat
replied to the thread
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Fundamental representation and adjoint representation
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I don’t know, I don’t use Zee’s books. May be he wants to introduce you to the adjoint representation, if he has not done that by this...
Mar 10, 2024
samalkhaiat
replied to the thread
I
Is the electromagnetic 4-vector indeed a 4-vector?
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Weinberg constructs the field a_{\mu}(x) from the polarization “vector” e_{\mu}(\vec{p}, \sigma) and the annihilation and creation...
Mar 6, 2024
samalkhaiat
replied to the thread
I
Is the electromagnetic 4-vector indeed a 4-vector?
.
The mathematical details is given on the pages 248 and 249 of Weinberg text. The math is easy if you are familiar with the technics of...
Mar 6, 2024
samalkhaiat
replied to the thread
I
Is the electromagnetic 4-vector indeed a 4-vector?
.
It is the point, A_{\mu}A^{\mu} is not physically meaningful quantity because it is neither gauge nor Lorentz invariant. I don’t know...
Mar 6, 2024
samalkhaiat
replied to the thread
I
Is the electromagnetic 4-vector indeed a 4-vector?
.
The potential with index up is not a contravariant Lorentz vector because it does not transform like A^{\mu} \to...
Mar 6, 2024
samalkhaiat
replied to the thread
I
Is the electromagnetic 4-vector indeed a 4-vector?
.
Gauge invariance must hold in all Lorentz frames, otherwise no physical meaning can be associated to a given quantity. Also, the...
Mar 5, 2024
samalkhaiat
replied to the thread
I
Is the electromagnetic 4-vector indeed a 4-vector?
.
The potential A_{\mu} is NOT a 4-vector. The fact that we can always choose A_{0} to be zero in ALL Lorentz frame show that A_{\mu}...
Mar 5, 2024
samalkhaiat
replied to the thread
I
Fundamental representation and adjoint representation
.
Exercise: Consider the transformation of your tensor T under the rotation R \in SO(n): T \to \bar{T} = RTR^{-1}, Now consider the...
Mar 2, 2024
samalkhaiat
replied to the thread
I
Noether's Theorem in the Presence of a Charged Operator
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It is not clear what meaning one can associate with the product of operators on the left hand side. I you have an exact symmetry, then...
Feb 5, 2024
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