Re: Solve the following equations algebraically. Give solutions as exact values where 0≤x<2π
I think I got it now :)
2tanxcosx = tan
2tanxcosx - tanx = 0
tanx(2cosx - 1) = 0
tanx = 0, ===> x = 0, x=pi, and x=2pi >==========< ANSWER
Also,
2cosx -1 = 0, ===> cosx = 1/2
x = pi/3, and...