Recent content by schamp

So I went back and checked my differentiation on the second derivative. Turns out I need the product rule: d/d(theta)[dy/d(theta)]=d/dtheta(dy/dx*dx/d(theta)) By the Product Rule: uv' - vu' where u = dy/dx du = d2y/dx2 v = dx/d(theta) dv = d2x/d(theta)2 Therefore...

Homework Statement Show that the differential equation: sin(theta)y'' + cos(theta)y' + n(n+1)(sin(theta))y = 0 can be transformed into Legendre's equation by means of the substitution x = cos(theta). Homework Equations Legendre's Equation: (1 - x^2)y'' - 2xy' + n(n+1)y = 0 The Attempt at a...