Recent content by scot72001

so would the following look ok for the first part? f(x) = {e^-αx^β } {αβ [x^(β-1) } x ≥ 0, α>0, β>0 and for the second part it should look like f(x) = { (1 + αx)/2 for -1 ≤ x ≤ 1, -1 ≤ α ≤ 1 to start off. apologies for missing the x as it is crucial. do you think i can still use 1+α as a...

sorry i just noticed it said put homework in the homework section after i had posted it in the first location

cdf to pdf and vise versa hi i'm looking for help when going from a cdf function: F(x) = { 1- e^-αx^β x ≥ 0, α>0, β>0 { 0 x < 0 to getting the corresponding pdf also i am looking to do the opposite(pdf to cdf) for: f(x) = { (1 + α)/2 for -1 ≤ x ≤ 1, -1 ≤ α ≤ 1 { 0 otherwise i'm...

hi i'm looking for help when going from a cdf function: F(x) = { 1- e^-αx^β x ≥ 0, α>0, β>0 { 0 x < 0 to getting the corresponding pdf also i am looking to do the opposite(pdf to cdf) for: f(x) = { (1 + α)/2 for -1 ≤ x ≤ 1, -1 ≤ α ≤ 1...