Recent content by Seneka

Thanks. How do I delete/close this thread?

My exams in three days...

There's not much to read. The diagram says it all. The procedure just says to swing the bung in a horizontal circle until the suspended weight remains stationary as this is when the weight is equal to the centripetal force. The paperclip acts as a marker to make this movement clear. It's...

I've adjusted it now.

Random error would be to do with not swinging the bung in a perfect circle so when I try to measure velocity, that would vary. Measurement of radius. How would I decrease percentage uncertainty? Use a smaller mass so that I get a larger radius so I can measure a longer length.

Thanks @RPinPA @Mark44 I was more confused as to why row switching worked. A nice explanation I found was by looking at what the determinant does. By looking at a simple two by two the determinant will give you an area of a parallelogram. When you add a row to another one that creates a...

But won't that change the value of R1 which will be equal to 3 instead of 2.

Dw I got it, thanks!

Thanks

I think it was an error. I got the right answer when I used my calculator to find the probability of less than and equal to 6 no errors and then subtracting from 1.

Yeah I realized but now I am getting 2.03..x10 to the power -34 My calculation as 12choose7(e to the power -1.6) to the power 7 multiplied by (1-(e to the power -1.6)) to the power of 5 and carried this pattern until I came to 12...is this wrong?

Are you suggesting doing a cumulative binomial distribution up to 5 where the probability of no error is e to the power -1.6?

So I thought you would find the probability of having 0 errors when the mean rate is 1.6. Square that by 5 and multiply that by one minus the probability of having 0 errors to the power of 7. So that is basically the probability of having 0 errors to the power of 5 multiplied by the probability...