Recent content by sess

Ahhh, I see what you are saying: T-mgsinθ-(μk)(mgcosθ)=ma So that would be- 500N-138N-85.8N=ma 276.2N/30kg 9.2m/s2 Which is the correct answer. Thanks guys, I really appreciate your help.

Oh, yes, sorry, I posted this question when I was going to bed last night and I was very tired. :P The slope of the incline would be 28°. I see what you mean about not resolving the tension into components now. And yes, the rope would be pulling it up the incline. So how would I go about...

Homework Statement A rope applies a force T = 500N as shown as the 30kg block moves 14m along the incline. The length of the incline is unlimited. The coefficient of friction between the block and the plane is 0.33 What is the acceleration of the block? Homework Equations \SigmaF = ma...