When I said same voltage I meant a nominal voltage applied to each bulb individually to find the resistance. Other solutions use 120V as this nominal voltage and R=V^2/P. This finds the resistance at the voltage and power ratings of the bulb. Using this method gives a higher resistance for the...
Hi
Two lightbulbs in series, one with 50W one with 100W which is brighter. I have two different solutions and can't see my error. Using PR=V^2 and I^2=P/V 50/√50R1=100/√100R2 with the same current and R2=2R1. Using PR=V^2 and the same voltage across both bulbs yields 50R1=100R2 or R1=2R2. Which...