Recent content by SgtSkittles

Oh. My. God. That makes much more sense. Thank you!

Voltage! Then if the voltage is the same, so actually it would be 7.229/1.207 which equals 8.7254 . Then the charge for C4 would be Charge/4.25 and then I'd do the same for C2. C4 (charge is 8.7254, voltage 2.053v) and C2 is (8.7254 charge, and 2.685v). So, now all that would be left is...

I got the voltage is equal to 10.48v and the charge is 12.651

Well, since C2345 and C1 are parallel, I'm going to say they would compare by the voltage sum of C2345 is equal to the sum of C1. If that's the case, nothing I do, gets 2.493 for C3 and C5. I tried doing 12.651 (charge of C1) divided by 1.207, but just get 10.481 and if I subtract that from...

I'm confused, I'll give it a shot though. But, to do that would I use the charge I got for C123456, C6, or C1 to find the voltage for that combo?

Wow, can't believe I didn't think of that. lol. Btw I just tried doing that with the hint my teacher gave, and I'm not getting anything near C3 and C5 = 2.493.

Homework Statement I am very lost, I tried everything I can do to find the voltage/stored energy for each capacitor, but no luck. I know that for parallel, V1=V2=V3 etc and stored energy is Q1+Q2 etc. And for series it's the opposite, but I'm getting completely different numbers for both of...