Recent content by shabut NAA

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    How high do you need to be to weigh 69.7 percent of your surface weight?

    Not really sure what g you're referring to, but I can give you the Gravitational Constant and the mass of earth: Gravitational Constant= 6.67x10-11 Mass of Earth= 5.98x1024
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    How high do you need to be to weigh 69.7 percent of your surface weight?

    How far above the surface of Earth would you weigh 69.7 percent of your surface weight? This is the work I've done but something isn't right and I'm not getting the right answer: 69.7(9.8)=6.67x10^-11(5.98x10^24)/r^2 = 683.06 = 3.98x10^14/r^2 r= 763329.61m (Incorrect) someone please...
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    I have a few problems dealing with work and kinetic energy

    Thanks, I got the 3rd one right now! 1st I don't really understand how I can find the F for W=Fd. I could figure it out if they gave me time but they didn't..so how can I go about finding the F?
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    I have a few problems dealing with work and kinetic energy

    1. A 0.267 kg ball is thrown straight up from 1.81 m above the ground. Its initial vertical speed is 8.00 m/s. A short time later, it hits the ground. Calculate the total work done by the force of gravity during that time. I know that I will probably need to use the PEg=KE formula, but I am...