Recent content by Shanghai Babe

i am not here for the pupose that people are doing my homework. i don't understand what u meant by " what are you thinking about this problem". 50xcos70=17,10N 50 stands for the force (which is given) and 70( is given too) for the angle. relating to 1b) torque is the tendency of a force...

for 1b i got : 50xsin70=46,98 T

@ Simon Bridge spare me the comment! if u don't want to help don't reply!

i already tried to calculate it. for 1a) i got 17,10N as result. but i am not sure if its right. I calculated : 50xcos70.

searching for equation for translational equilibrium for horizontal components of force

hey everybody :) i am new here and i need ur help. I have to solve this problem for home work tomorrow.Topic is forces in the body. I attached it. I actually need help for the whole first question. thx u in advance. Please try to explain it not too difficulty. thanks u :) Homework...