Recent content by Sherry Darlin

I'm looking to do a course on Optimisation, however there was no prescribed textbook and I'm a bit wary of doing a course without a textbook to reference. There was a generalised list given, of like 10 textbooks, but this is a bit too much, especially with 3 other subjects to do! Here is the...

C stands for the capacitance, and R is the resistance. I guess I should have said C and R are non-zero. I would put the circuit diagram, but it wouldn't make sense unless you can understand it, although it's pretty easy. I'm not sure what you mean by are they related. It's like having an...

I'm inclined to agree with haruspex, based on what I saw on the graph I broke it down from [0 - 60] and [60 - 150] and [150 - 180], it's rather vague to me. Maybe it would make more sense to someone who deals with internal combustion engines specifically? Googled it?

I did it slightly differently to you, although I got the same answer I didn't quite understand your method. If integrating from 0 to 180 degrees (half a revolution) produced 1040 J/s, then one complete revolution (360 degrees) produces 2080 J/s which is 2080/60 = 34.6667 J/m Multiplying by...

I'm a bit confused by the graph, after 180 degrees the cycle commences again as at 0 degrees? If so, wouldn't the greatest fluctuation in energy be the region covered by the steepest slope? Which appears to be from 0 - 60 degrees. I don't know much mechanical engineering principles so I might...

Yes: http://www.wolframalpha.com/input/?i=integrate+3+%2B+x*sqrt%28x%29+from+-1+to+4

Homework Statement I have a transfer function as part of a circuit analysis question which I obtained as: -{\frac {{\it R2}}{ \left( {\it sC1}\,{\it R1}+1 \right) \left( {\it R2}\,{\it sC2}+1 \right) }} Which needs to be turned into: The Attempt at a Solution I have...