Recent content by Sidhshah1234

d) W=1/2kx^2=PE 41000=1/2(k)(33)^2 k=82000/(33)^2 k=75.3N/m (nowhere close to the answer) e) Potential Energy = Kinetic Energy mgh = 0.5 * m * v^2 Given: m = 26 kg g = 9.8 m/s^2 h = 160 m Solving for velocity (v): 0.5 * 26 kg * v^2 = 26 kg * 9.8 m/s^2 * 160 m v^2 = (2 * 9.8 m/s^2 * 160...