Recent content by sidnygte

so then the function in terms of x would be V = 1/3X^2 * sqrt( sqrt(128)-x)^2 - (0.5x)^2) ? that seems confusing haha. has would I simplify the double square root? Since it is being squared in the inside can I make it into V = 1/3X^2 * sqrt(128 - X^2 - 0.25X^2)?

so what would the equation look like if you were trying to get H to the power of one? h = sqrt(l^2 - .5x^2)?

ohh that changes it a bit so h^2 = l^2 - (x/2)^2 so you can square root everything so h = l - (x/2)? that doesn't seem right

Homework Statement I am given an 8in x 8 in piece of paper and I need to build a pyramid with a square base with the greatest volume. Homework Equations V = 1/3 * x^2 * h b = base length h = height length I'm trying to get everything in terms of x, which is the length of the base of the...