Recent content by SirKhairin

  1. S

    Minimum refractive index for total internal reflection at 45 degrees

    Homework Statement I uploaded the question below.2. The attempt at a solution At first what I did was using the Snell's Law formula n_1 \sin{\theta _1}=n_2 \sin{\theta _2} then I did this, n\sin{\ 45}=1 \sin{\ 90} so this is the minimum value that I got n=1.41 I'm not sure if my answer is...