Recent content by SK97

so i finished calculating for all C values and after the addition got to 7/2 as the answer. does that seem right to you?

Thanks a lot! hopefully i don't run into other issues but please be around to help out! will greatly appreciate it :)

oh thank you so much, so similar set up then for the other integrals and then at the end its just addition of them all, correct?

so replacing x with t we get t^2 in the integral but since z= 0 do we get 0 for c1? sorry if I'm understanding incorrectly

just t^2 dx right?

So for C1 i have the parametrisation as r(t) = <t,0,0> I got this by doing: x= t(1) + (1-t)(0) = t and zeros for the others. Is this the correct way to evaluate it?

Okay, so i form three integrals and combine them? Also that's where i am confused, when i am doing C1 shouldn't the 3dz go away too as its treated as a constant?

Hi all, I'm finding it difficult to start this line integral problem. I have watched a lot of videos regarding line integrals but none have 3 line segments in 3D. If someone can please point me in the right direction, it would help a lot. I've put down the following in my workings: C1...

Yeah that seems to make sense. Thank you again for all your hard work!

So it's just the nature of the question that made both values close to each other? All in all thank you so much for your thorough help in this problem, I can't tell you how much I appreciate you and am thankful for helping me understand this topic clearer.

ok here it is: Ea for 260V: Vdc - IaRa 260 - 30(0.25) = 252.5V Ea for 300V as calculated before is 292.5V T (260V) = 252.5 (30) / (1276.36) (2pi/60) = 65.65 Nm T (300V) = 292.5 (30) / (1276.36) (2pi/ 60) = 56.67 Nm now : T (300V) / T (260) = I (f) 1 / I(f) 2 65.65 / 56.67 = 5/ I(f)2...

Yes so after doing the method i posted earlier, I am still obtaining an answer of 20 ohms. So something I'm doing must not be right, but i can't understand what?

Okay so applying that method; After i get the torques in the two cases is it correct for me to do this: T(300V) / T (260V) = I (f) 1 / I (f) 2 where I (f) 1 is 5A and I (f) 2 is unknown. Also is the Wm (mechanical speed in radians) the same for both volatges?

I think my confusion is lying in what i exactly equate at which step. For the first step of the solution do i use the equation T = Ea * Ia / Wm For both 300V and 260V to get the torques for both? Then i would need to relate that to field current I(f). So where does mechanical power come...

would i do that for both voltages? use the back emf generated to get the torques?