Recent content by skeeve

With all of these previous pieces of information, I have one more question. How is a new weight calculated of an object that is has been falling? I'm going to add a couple things here. Let's assume the small cylinder weighs 5 lbs, and the large cylinder weighs 10 lbs. The smaller cylinder...

Dpiston=inside big pipe=2.067in Ap=∏(Dp/2)2=∏(2.067/2)2=3.356in2 Fp=300lb Pg=Fp/Ap Pg=300lb/3.356in2=89.39psi

.Scott, I'm not sure how exactly this will affect the situation, but the smaller tube will have a small groove cut into it to hold the rubber ring, probably a bit of glue to try and hold it. To make it simple, there will be some kind of oil on the inside of the large tube to take away as much...

I've probably put more information then necessary, but it's been a while since I've taken a Physics class (which I love) and can't find my old textbook, so I didn't want to risk anything. I'd appreciate any recommendations for a good website that talks about this concept and includes some...

Oops. I forgot to put in the diameters. id=inside diameter, od=outside diameter Big Pipe od: 2.375 in Big Pipe id: 2.067 in Small od : 1.900 in Small id : 1.593 in

All right, let's try adding some numbers here. Large pipe length minus inside stopper length: 5 ft Small pipe: 5 ft (pretend stopper doesn't expand beyond the top of the pipe) Weight on top: 300 lbs Average external air pressure: 14.7 psi Please include the basic equation(s) that you...

Consider the following: I have 2 PVC pipes, one is small enough to fit into the other with a little extra space. A rubber ring is placed around the smaller one to fill up the empty space, making a good seal to push air in and out of the larger one. Ignore any friction caused by the ring on...