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Electric Fields , Finding final velocity. NEED HELP
I get it W=FD W=125N x.12 W= 15 F=(9x109)(25x10^-6)(8x10^-6)/(.2^2) F=45N W=45 x .2 W= 9 pe=pe' + ke' 15= 9 + 0.015(v^2)/2 v= 28.28 Thanks!- skye204
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- Forum: Introductory Physics Homework Help
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Electric Fields , Finding final velocity. NEED HELP
Homework Statement Mass= 15g Q1= 8.0uC Q2= 25 uC (stationary) Q1 is released from a point 12cm from Q2. How fast will Q1 be moving when the separation is 20cm. Homework Equations F=ma F=qe F=kQq/r2 E=kQ/r2 Ke=mv2/2 W=FD vf2=vi2+2ad The Attempt at a Solution...- skye204
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- Electric Electric fields Fields Final Final velocity Velocity
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- Forum: Introductory Physics Homework Help