Recent content by slowle4rner

So...A^3+b^3 = (a+b)(a^2-ab+b^2) 4y^3+4 = 4(y^3+1) = 4(y^3+1^3) = 4(y+1)(y^2-y+1) That's basically what I came up with. I guess I am confused because I 4 is not a perfect cube and I didn't realize you could factor out the 4 and work the problem from there. But I suppose this makes sense...

I'm having trouble factoring the following binomial... can someone try to point me in the right direction please? 4y^3+4 It has been 7 years since I took algebra and I am trying to get my review done. This one just does not make sense to me right now... Thanks!