Doing that I got Fb = Mg - Ma AND Fb = mg + ma
Mg - Ma = mg + ma
Solving for m (mass discarded), I get
m = M(g - a) / (g - a)
Crossing out the term (g - a)
m = M
This doesn't quite make sense to me, and it's not inline with the answer the teacher gave us.
I'm going to...
Sorry if I appear dense, but i don't believe we're supposed to consider buoyant forces (I don't even know what that is to be honest). I'm having a little difficulty following your steps here. You're saying initially that the Force of Buoyancy (Which I am just assuming is the force of the lift of...
Homework Statement
Hot-air balloon of mass M is descending straight down with acceleration a. How much Mass must be discarded to make acceleration a the same magnitude, but directly up instead of directly down? Disregard wind resistance/lift.
Homework Equations
The only one my book...