Recent content by Soicowboy

So you wouldn't include the 50mm on the line and just work off 300mm?

Haha yup that makes total sense, wasn't being logical and focusing properly.

I think I solved it ?

70 / 0.05 = 1400N ? For part b of the problem. Would you divide the first anwser to find out how much more force is required to generate another 100N. Thank you so much!

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Would the same equation and using a FBD and sum of forces be applicable to this problem. Really appreciate your guys / girls time thank you.

CM = CCM A x 0.025 = 50N x 0.085 A x 0.025 = 4.25NM A= 4.25 / 0.025 = 170N?

Ok thank you I'll rework.

0.085m

Thanks a lot I'll look up and learn those concepts and post my working. Appreciate your time thank you

Hi guys I'm studying at home over lock down would anybody be able to point me in the direction of some online learning material or what concept I should look up to solve this problem and find formulas . I'm stuck and can't find anything relevant online while searching. Thanks guys any help is...