Recent content by soolights

no problem, but shouldn't you be right if we are solving for M2? all the m2 should be on the LHS right?

therefore since we're looking for m2 and only m2 we can simplify to m2=(m1+m2)a /g?

oh, i missed that message, sorry T=M1a , a = T/M1 M2g-T=m2a , M2g-T=M2(T/M1)

OK let me try again lol this isn't going too well for me is it m2a = w-t m2a = m2g-t m2a-m2g=-t m2(a-g)=-t m2=-t/(a-g)

so m2a = w-t, how to get rid of w?

okay, so force in the y direction is both tension and gravity, so fnet = w-t (is necessarily w>t?). so w-t = m2a?

i'm not sure what else there is to put...normal, tension, gravitational forces are all there and i don't know of any other ones that are applicable?

so, for tension and weight..?

this is the FBD I've been using--

oh gosh! since there's no friction and it pulls downward, it's just 9.81. fnet = t, so using fnet = ma, m2 = t/9.8?

so the only force is the tension...but how does that link to the mass of m2 hanging off the table? m2's only force is the tension force holding it up..

fnet = ma, so m = fnet/a? i don't know if this will help or not because it doesn't provide acceleration :/

no, it doesn't make a circular motion. we just don't know the acceleration of the system. everything is linear! (these problems should be solvable without a calculator) the tension force is acting on M1 and pulling it toward the edge of the table, along with the gravitational weight force and...

yes i made a mistake, we don't know which way it moves

i don't understand how to list these out with so few information. there's nothing given for acceleration, movement, or relationships between anything...?