Recent content by Sophie Martinez

So the complete one would be TME= v^2/2 + gh?

I ended up with F•d=mgh and F•d=(mv^2)/2 because of the work-energy principle. I also tried to isolate m in each case and equated the two results and got (F•d)/gh=2(F•d)/v^2

I think the equation would only be TME=(mv^2)/2 but because the mass is canceled it would be (v^2)/2?

Homework Statement A bead is sliding on a surface. At point A it is 80 cm above the ground, at point B it has just hit the ground and at point C it is 50 cm above the ground. At point A it has a speed of 200 m/s, so what will its speed be at point B and C? Homework Equations W=F.d Kinetic...