Recent content by sowarefuc

I have progressed with the book. Slowly but surely, and it's getting easier. Or at least, I'm getting used to make my own proofs much faster. Questioning every statement I make when trying to come up with a proof is helping a lot, just thinking whether whatever it is that I'm doing is really...

I think part of the problem might be that we only know the basics. We have only worked with one frame. For example, I don't know what you mean by "rings". It wasn't until I was introduced to matrices that I worked with something new, with a new basic set of rules to learn. I will take a look...

Yeah that's what I mean, apparently I had to do something like (a*b^-1) * (c*d^-1) = (a*c) * (b*d)^-1 = (ac)/(bd) I don't know how to format the way you do it though, sorry about it. I followed my professors notes, which were not very in depth. I'm usually good with the computation side of...

It is great to know that I will work with mathematical proofs so that this will actually be helpful. Oh I didn't even think about matrices. That's also a good point. Thanks for the answer and for giving me a practical example.

This is a very good answer and a very good reason to stay with this book. I particularly liked "No harm will be done, if you fail in a proof, but the practice can once be valuable with a roof." Thanks a lot.

Hey, I have been told to study calculus following Spivak's book. I was in an Engineering program and I have moved to a Physics one, and I want to retake calculus to really get good at it. The problem is, Spivak's seems to me like it's very proof based, and I'm having a hard time even with the...

I've been out for a few days, but now it's done, thanks for taking your time to help me!

How is the second constraint not correct? If I differentiate v more than q times, I get zero. Therefore, for v(k)not to be zero, k must be smaller than q, or equal, I used the same logic procedure for the first constraint. Shouldn't it be more appropriate to have a combination like C(p+q, q)...

For u(p+q-k), k≥q, otherwise it's zero. For v(k), k≤p, otherwise it's zero. Therefore, we have this: q≤k≤p. What's the goal of setting this constraints or limitations to the values of k? I thought that the terms between parenthesis after the Σ were a matrix, now I think I was wrong, what is...

That's an interesting point, I didn't realize the k>q condition. So we have: y(p+q)=(n(n-1)...k)u(k)·[q!/(q-k)!]·(1+x)(q-k) I don't know how to put (n(n-1)...k) in a simplified way, or (q-k)!. ----------------------------------------------------------------------- I have a different approach...

Trying to get an expression for v(k), and being v=(1+x)q ,I get: v(k)=(q(q-1)(q-2)...(q-k+1))(1+x)(q-k). Which I believe is wrong, mostly because you said we are seeking for a formula with only x,p and q as variables. If I plug the expressions I'm getting so far into the formula, it looks messy...

Do you mean I need to differentiate u (n-k) times? If so, I can make an expression like: D(n-k)un=(n(n-1)(n-2)...k)⋅uk. Which I don't think it's what you meant. If I differentiate u alone, It would go like: D(xp)=px(p-1) So Dp(u(p))=(p(p-1)(p-2)...1)⋅x(p-p)=p! I think the problem relies in the...

Homework Statement Statement:[/B] Let y = u(x)v(x). a) Find y' , y'', and y''' b) The general formula for yn, the n-th derivative, is called Leibniz’ formula: it uses the same coefficients as the binomial theorem , and looks like https://i.gyazo.com/53728964c6b3ef142fd70f600c29e037.png Use...

Thank you all for the help and the insights. I will send my application to the engineering school, I think I will have a great time working in engineering, let it be Materials, Aerospace, or the "Doble Grado de Ingeniería Eléctrica y en Ingeniería Electrónica Industrial y Automática", which...

And having in mind what I said about nano stuff? For you to have an idea, my dream would be to work somewhere like MIT.nano, in order to get there, do I need to study engineering or physics? In case of engineering, which ones?