Recent content by space_yes

Thanks for the reply! I actually ended up getting the right answer b/c I worked out the problem out in mathematica and it correctly simplified. However, I didn't notice (what you and Mathematica did) the discrepancy between my written work (posted) and my code ergo my erroneous function y(120)...

I figured it out... the step where I let k = e^c is the problem. Leaving e^c and continuing we would have: y = e^(4c)/(250+4t) Letting k = e^(4c)... y = k/(250+4t) Solving for k = 15000... Now solving for c to find the numerator in the expression for y... 15000 = e^(4c) c =...

I raised both sides to powers of e to remove the natural logs so I can get an expression for y... ...should I be doing something else there?

Homework Statement Alright, I know this has been done in various incarnations but I haven't found an example exactly similar to mine.. A tank contains 60kg of salt and 1000L of water. Pure water enters the tank at the rate of 8L/min. The solution is thoroughly mixed and drains at a rate...