Oh, I get it. So I could write it like this:
(x-a)^2 + y^2 = a^2 (cos^2(2x) + sin^2(2x))
Then the identity takes care of the rest so I'm left with
(x-a)^2 + y^2 = ^2 , right?
Homework Statement
I have been given these two equations:
x=2acos^2(x) , y = 2a(cos(x))(sin(x)) where a ranges from 0 to 5 and -2π < x < 2π
I need to prove that these equations (when you plug in values for x) create points that when plotted, give you a circle with center (x-a) and radius a...