Recent content by steph2010

0=-25=32.64t-4.905t^2 t= -.88s t=5.77s

ok so t= 5.77 sec

what y and x equations?

now i have to answers for t 2.04sec and 2.5sec

t= 2.51 sec

i am getting the answer to be 21.9264m is that right?

but arent i finding the where it would land on the y axis?

a cannon located 60m from the base of a vertical 25m tall cliff, shoots a 15kg shall at 43 degrees above the horizontal toward the cliff (a) what must the minimum muzzle velocity be for the shell to clear the top of the cliff? (b) the ground at the top of the cliff is level, with a constant...