Recent content by SteroidalPsyc
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Simple harmonic motion (finding omega)
O ok haha sorry I'm really tired. Thanks for the help I solved it!- SteroidalPsyc
- Post #5
- Forum: Introductory Physics Homework Help
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Simple harmonic motion block question
So did I just forget the (-)? v(t) = -Awsin(wt)- SteroidalPsyc
- Post #5
- Forum: Introductory Physics Homework Help
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Simple harmonic motion (finding omega)
I don't know what k is though. How do I find k?- SteroidalPsyc
- Post #3
- Forum: Introductory Physics Homework Help
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Simple harmonic motion (finding omega)
Homework Statement A particle executes simple harmonic motion with an amplitude of 2.51cm. At what positive displacement from the midpoint of its motion does its speed equal one half of its max speed? Homework Equations A=2.51 cm x(t) = Acos(wt) v(t) = -Awsin(wt) vmax = |-Aw| The...- SteroidalPsyc
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- Harmonic Harmonic motion Motion Omega Simple harmonic motion
- Replies: 5
- Forum: Introductory Physics Homework Help
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Simple harmonic motion block question
What exponent did I drop? I'm confused... So i guess i should change everything to m? you said not to forget units on this part. Are the units going to be N/mkg ?- SteroidalPsyc
- Post #3
- Forum: Introductory Physics Homework Help
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Simple harmonic motion block question
Homework Statement A block of unknown mass is attached to a spring of spring constant 6.7N/m and undergoes simple harmonic motion with an amplitude of 7.8 cm. When the mass is halfway between its equilibrium position and its max endpoint, its speed is measured to be 38.5 cm/s. (a) Calculate...- SteroidalPsyc
- Thread
- Block Harmonic Harmonic motion Motion Simple harmonic motion
- Replies: 4
- Forum: Introductory Physics Homework Help