Steve4Physics's latest activity

The non-slipping condition is simply required to enable the cone to rotate around the vertical axis. Friction provides the centripetal...

That's a pity - I thought it [my Post #10 formulation] was quite good! How could it be improved? Yes - then the solution is nearly...

Possibly something like this... A solid right circular cone of uniform density has mass m, height h and a base of radius r. ‘V’ is the...

A line can't be perpendicular to a point. You probably meant to ask: "Aren't gravitational field lines always straight and directed...

I'll explain! In Post #24 you wrote: I looked at the link. The first (remarkable) sentence of the abstract is this: "The foremost...

My wording was very poor. It was not the intended meaning. (But I hope the intended meaning was clear from the latter part of the post.)...

I may misunderstand the issue you are indigating. But to try to answer your question... Take three conducting plates (equal sizes...

Well, I'm not sure if this answers your question but here’s a qualitative (definitely not rigorous) attempt... Thinking visually, a...

@tellmesomething, this might resolve specific issues you raised…. ‘Ground’ and ‘infinity’ are not necessarily equivalent. I believe...

Thank you all for explanations. I tried to prove this to myself by contradiction, but it might be an oversimplification. If we assume...

Hi @tellmesomething. I understand what you mean - sorry for not picking it up sooner. I’ve edited what I said in Post #8 as it may be...

The initial net charge is non-zero. But when plate-3 is grounded, charge will flow between the system and ground. The final net charge...

The Post #1 diagram is misleading. It would be better to include an open switch in the earthwire and ask something like: "What are the...

I don’t think that’s correct – there will be discontinuities in charge-densities and field-strengths as you move left to right. To add...

I think you are right. The book solution implicitly assumes that the voltage at the bottom of slab 1 is constant across the width, which...