Recent content by steven cheung

i need some time to think,because i learn limit on 3 days

so, -a|b-3| if put in x=-1 then, a is all real number, b is 3 ?

(-a)(b-3)>0 b-3>0 or -a>0 b>3 0r a <0 that right?

i do not understand have some tip?

Homework Statement For what value of the constants a and b such that the following limit exists? lim {(ax+|x+1|)|x+b-2|}/|x+1| x->-1 help me ,thx Homework EquationsThe Attempt at a Solution first, I know that I should cancel the absolute value at denominator of x+1. but i don't how to...