Recent content by strick

can anyone please help?

F = BiL I used the cosine Rule to express dL-> dL = (2Rsqu. - 2Rcos dθ)squ root therefore dF at particular point = Bi(dL)/sinθ But i think I am in a totally wrong direction. I think i should set up a function so that the total area under the curve equals to the vertical force acting downwards...

i think the horizontal resultant force around the arc should cancel out, however, i m still stuck in setting up the equation for the vertical resultant force around the arc.

Figure below shows a length of wire with a central arc, placed in a uniform magnetic field B that points out of the plane of the figure. If the wire carries a current i, what resultant magnetic force F acts on it? Express the answer in terms of B, L, R and i. I am stuck in this question for...