Recent content by stuck
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How Do You Simplify Complex Trigonometric Expressions?
would it be: (sin^2x) x (1/sinx) = sin^2x/sinx (sin^2x/sinx) x (1/cosx) = (sin^2x)/(sinx cosx)?- stuck
- Post #5
- Forum: Precalculus Mathematics Homework Help
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How Do You Simplify Complex Trigonometric Expressions?
there's a few... Write each expression as a single trigonometric ratio or as the number 1. 1) sint+(cott)(cost) 2) (sec x)(sin^2x)(csc x) For number one I went like this: sin t + ((1/cot)(cos/1)) sin t + (cos t/cot t) sin t + (cos t/1)( sin t/cos x) (sin t cos t)/1 + (sin t cot...- stuck
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- identities Trig Trig identities
- Replies: 5
- Forum: Precalculus Mathematics Homework Help
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Can You Solve This Trigonometric Identity?
I got it, Thank you!- stuck
- Post #7
- Forum: Precalculus Mathematics Homework Help
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Can You Solve This Trigonometric Identity?
I think I can I didnt know that before, I will try to work it out now!- stuck
- Post #5
- Forum: Precalculus Mathematics Homework Help
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Can You Solve This Trigonometric Identity?
Urk, I thought that because in my third step on the left I had (cos^2A) and (-cos ^2A), that they would cancel...?- stuck
- Post #3
- Forum: Precalculus Mathematics Homework Help
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Can You Solve This Trigonometric Identity?
Prove the following identities: (cos A = cos B)^2 + (sin A + sin B)^2 = 2[1+cos(A-B)] I'm really a mess at this stuff. I missed a few important days and fell behind, so I don't reeeally know what to do when things start getting squared and whatnot., but I tried! :bugeye: Left Side...- stuck
- Thread
- identities
- Replies: 7
- Forum: Precalculus Mathematics Homework Help