Recent content by Sudesh

Okay. Is this correct? Therefore : F=ma ⇒ 0.3 kg * 0.01 m/s^2 ⇒0.003 N T = F* pitch rad where Pitch rad = 0.25 in ⇒ 0.00635 m T = 0.003 * 0.00635 ⇒ 0.00001905 Nm ⇒ 0.0001686067 lb.in Max s = rpm * radius * 2π max s = 3 m/min ⇒ s = 9.8 ft/min radius = 0.25 in ⇒ 0.02 ft Therefore rpm = s /...

I have come up with this calculations - is this correct ? s=1/2*a*t^2 time t = 10 sec ⇒ 0.16 min Therefore a = 2*3 (m/min) / (0.16)^2 ⇒ a = 234.3 m/min^2 ⇒ a = 0.065 m/s^2 F=ma ⇒ 0.3 kg * 0.065 m/s^2 ⇒0.0195 N T = F* pitch rad where Pitch rad = 0.25 in ⇒ 0.00635 m T = 0.0195 * 0.00635 ⇒...

Okay. I have these dimensions for the rack & pinion - SPUR PINION Diametrical Pitch (= T/d) 24 Number of Teeth 12 Pressure Angle 20 deg Max. Pitch Diameter 0.5 inch Face Width 0.25 inch Bore 0.25 inch Hub Projection 0.31 inch Hub Outer Diameter 0.39 inch SPUR RACK Pressure Angle 20 deg Face...

Calculating from this the time = 0.5/3 min which equals to ~ 10 sec [SIZE=16px][FONT=PT Sans]

Okay. Time is not a major constraint for me. The main criteria is the motor should have less than 50 Hz frequency (if this information helps) The speed for moving the load = 3 m/min and distance = 0.5 m

Yes, I understand that. Hence, the load would be supported by another rod which is not part of this mechanism. We can neglect any frictional and efficiency losses too for the calculations if it makes easier for solving.

I have attached the diagram above

This is the link for a similar setup -

Hi, Could someone please help me with this. I need to move an object which weighs 300 g horizontally, which is linked to a linear actuator consisting of rack and pinion arrangement which is driven by a servo motor. The speed at which the object should move is 3 m/s and the distance is 0.5 m...