Recent content by Sunfun

Yes I have. Thank you so much!

So it is the difference between the initial kinetic energy and the final kinetic energy+rotational energy?

So how would that give the mechanical energy?

So for the mechanical energy, does the bullet have kinetic energy initial=the rotational energy of the block minus the kinetic energy of the bullet final?

Isn't the angular momentum conserved?

So if that is the momentum, how is that related tot he rotational speed?

Homework Statement There is a small block of steel with mass 2.4kg and is firmly attached to a low mass wheel a distance .3m from its center. The wheel is free to rotate about a vertical axis and is at rest. A .0023kg bullet traveling with an initial speed of 305m/s in the horizontal plane...