Recent content by Syw

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    Car overtaking with constant acceleration at 2.0 m/s²

    Okay, so this is what I did and I got the answer 15 s. I’m not fully sure if the answer is right so do you know if I’ve done everything correctly?
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    Car overtaking with constant acceleration at 2.0 m/s²

    Yes, makes sense. It’s just that I don’t know how to tilt the line to get the proper answer in my graph. The reason I’m doing it is because I think I’ll understand it better once I can see it visually.
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    Car overtaking with constant acceleration at 2.0 m/s²

    I did a v-t-graph. But I get lost on what to do when it’s starts to accelerate at 10 seconds. This is what I’ve done so far. Any suggestions on how I can move forward?
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    Car overtaking with constant acceleration at 2.0 m/s²

    Hmm, that’s weird in that case, cause I’m in a beginner physics course and it just started, so I haven’t learned a lot yet. It’s strange if I a got a homework this hard like you said then. I’ve just been taught some basic formulas, so felt so lost when this problem came up. I do want to...
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    Car overtaking with constant acceleration at 2.0 m/s²

    Hmm, I can’t find anything about that in my course book, so no.
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    Car overtaking with constant acceleration at 2.0 m/s²

    This is why I’m here. I don’t know how to solve the problem and need help. Been struggling with this problem for a while now. Been googling, watching YouTube videos trying to figure it stuff out. Unfortunately, my teacher is basically not present to help and is bad at explaining. My course book...
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    Car overtaking with constant acceleration at 2.0 m/s²

    After 10 seconds, car A has driven 150 m and car B 200 m. The difference is 50 meters.
  8. S

    Car overtaking with constant acceleration at 2.0 m/s²

    This is what I've done so far: 54 km/h = m/s 72 km/h = m/s a = 2,0 m/s^2 A = d_1 = v * t = 15 * 10 = 150 m B = d_2 = v * t = 20 * 10 = 200 m d_3 = d_1 - d_2 = 200 - 150 = 50 m Don‘t know how to continue to solve the problem.