Recent content by T.S.M

Aahhhhh! i got ittttttt! :biggrin: •I made two equations, one equal to R, and other P, that is in both R and P were unknown and then solved it "simultaneously" :approve: Husshhh! Thank-you guys for Ur help, thanks alotttt! :D

For finding the normal reaction, R - (0.5g cos α) - (P sin α) = 05 * 0 (zero because, no acc. upwards) Now equation for the motion of direction (P cos α) - (0.5g sin α) - (0.5* Value of R) = 0.5 * 0 (zero because, speed is 'constant') So, am i going right? The magnitude of R which i m...

Hmm, i get what are you saying , but still 'P is UNKNOWN and R too' so 2 unknowns :P how can we solve it ;) And may be it's misprinting or something, how can they both be equal to 9.8! :/ Umm btw u tried it? :P Lemme know ASAP!

But reaction force can only be found out when we have the magnitude of P! And that's what we do't have! :S And the answer at the back of book is 9.8 N , both reaction force and P also! Both equal to 9.8 :/ Aaargh it's confusing! :O

Two particles P and Q of mass 2 kg and 3 kg respectively are connected by a light inextensible string. The string passes over a small smooth pulley which is fixed at the top of a rough inclined plane. The plane is inclined to the horizontal at an angle of 30°. Particle P is held at rest on the...

Hey Everyone, here's a question i have issue with :( A particle of mass 0.5 kg is pushed up a line af a greatest slope of a rough plane by a horizontal force of magnitude ℙ N. The plane is inclined at an angle 'α' (that is alpha) where tan α = 0.75 and the coefficient of friction between 'ℙ'...

Yep, i'm! :S That's what is confusing me! :O

Hey thanks! Yes yes i tried the way you told, that is keeping the acceleration the same, i got the answer right! :D Thank-you :) Errmm btw can you please tell me whether the theory, my teacher told is right or wrong?

Mechanics Kinematic General Concept question, not a numerical!? I'm really confused concerning the positive direction and the acceleration taken while concerning the motion of the ball! Well, the main thing that i wanted to ask is that if 2 balls are been projected at the same time in two...