Recent content by TahirMaqbool

So my book states torques perpendicular to the fixed axis of rotation tend to tilt the axis , however we assume sufficient restraints exist so these torques are simply ignored. It follows that angular momentum perpendicular to axis remians constant. (See image ) My question is that if a rod is...

The application of Boyle's law in that case wouldn't be done in a manner it is done

While I reserve a possibility of error, dont assume it is written by random nobodies. The book is standard textbook of chemistry across India, authored by numerous scientists. I could show you the cover page .any ways thankyou for your time

That's all fine , how will you explain this "Since balloon bursts at 0.2 bar pressure, the volume of balloon should be less than 11.35 L." A lesser volume will lead to a Higher pressure, isn't it wrong?

I finally got what I wanted, thank you all who showed interest

Thats correct and if you see my solution above (attached as an image)I got exactly same answer using pseudoforces. I just wanted to see is it possible to solve it by simply workenergy theorem applied from ground frame.

By the time particle reachs the horizontal diameter it would have some velocity,which would lift it further up, just like we throw a ball upwards ,just because gravity is pulling it down doesn't mean the it can't rise to some height.

Thanks for that answer , I am interested in solving from ist principles ,I think I do have a solution already but why can't it be done from the ground frame is my real question here. Work done by gravity bis same in both the frames just work done by normal reaction is bothering me.

Ist of all thank you so much for taking time to think over it, but you are upon error here .bead will have attained some velocity before the horizontal diameter and then it will deccelerate because of the forces which you have already shown. And even for the sake of argument it was to stop...

Basically the problem involves using workenergy theorem, a non inertial frame eats away work done by normal reaction. since the bead motion in a non inertial frame is always perpendicular to the the Normal reaction . Same , however,doesn't hold when you allow the ring to move and thus a...

I have attached the solution w.r.t a non inertial frame you may take a look

That would be true if one was to ask for the equilibrium location, however for maximum displacement this one isn't becoming easy(equilibrium doesn't mean maximum angular displacement) rather velocity should become equal to velocity of frame .thanks for the reply though

I apologise, I should have mentioned the ring is accelerated horizontally

Just curious, I got the answer from a ring centerd frame . I want to solve the problem from ist principle without involving pseudo forces . Infact I did get a matching answer from a non ring centerd static frame ,but I am not comfortable with some of the things I did there