Recent content by taki123

Its just a question set at university.

Sorry but could you please explain just a bit more I'm very confused. The work that I have worked out is the amount of work done right? So what am I dividing or multiplying it by?

Since Q=0 then W=deltaU so dividing them would just give me 1.

I see what you mean, but even if I did that how would I get to the efficiency of the compressor? I keep finding formulas for efficiency which include Q, but since its adiabatic Q=0.

1. 100kg of methane is compressed from 0.5MPa and 300K to 3.0Mpa and 500K in a closed chamber by a compressor. The compression process is assumed to be adiabatic, calculate the efficiency of this compressor. Specific heat capacity of methane under constant pressure is 35.58 kJ/k.mol.K and ideal...