Ummm... Now how do I do problems #2 and #3?
I made two more equations but they only account for the smaller box of weight 32kg,
Net Force X = 0 = -32*9.8*sin(27.76) + Fn*.756 (5)
Net Force Y = 0 = -32*9.8*cos(27.76) + Fn (6)
So through (6) I get Fn= 277.5 N, plugging that into (5) doesn't equal...
HI,
Yes, thank you for the fn*.756! However, I still get -159.3 as my answer, which is also wrong. How do you calculate friction force to be 301 N? I calculated it to be 693 N, which is not what you said. Maybe you mean:
Net Force X = -80*9.8*sin(angle) + Fpull + Fn*.435 = 0 (3)
This way I get...
Homework Statement
You are lowering two boxes, one on top of the other, down the ramp shown in the figure by pulling on a rope parallel to the surface of the ramp. Both boxes move together at a constant speed of 19.0cm/s . The coefficient of kinetic friction between the ramp and the lower box...