Thanks for all your help, greatly appreciated. So for question b I got 30.58m by using the formula W = m*g*d and rearranged to find d...is this correct?
There is 100N of force pulling the string back. I see your hint Hint: a change in KE is the result of work done by a force...
I don't understand that...or don't understand what I'm suppose to do with the 100N
I thought you were saying it wasn't elastic potential...and my book says elastic potential depends on mass of object, acceleration due to gravity and objects height. Is my book wrong? It says kinetic energy depends on speed of.object and the mass. But I don't know any speed...
My book says...
Energy associated to motion is kinetic energy
Soo..
PEg = m*g*h
PEg = (0.15)(9.81)(0.45)
PEg = 0.66
Sorry i still don't see how this is getting me the speed of the arrow. Thanks for your help and patience I have been out of school for 6 years.
The energy would transfer to the arrow. But how do I determine the speed? Does energy = speed?
Gravitational potential energy = Eg
Eg = mass x force x height above reference point
Elastic potential energy? It says that this form of energy depends on the mass of the object, acceleration due to gravity and objects height.
If I rearrange the formula for kinetic energy I can get the formula to get the speed. But don't know how to get the kinetic energy to solve the formula...
Homework Statement
An archer places a 0.15kg arrow on a boasting. Then the archer exerts an average force of 100 Newtons to draw the string back 0.45 meters. Assume that friction is negligible.
A) what speed does the bow give to the arrow? (5 marks)
B) If the arrow is shot vertically...