Recent content by tdenise

Thanks SammyS. For u = -2: P(3) = (P(1))^2, so (P(3))^2 = (P(1))^2 So P(x) is does not have a one to one y to x mapping (I don't remember the name for that). How does that help solve the problem though? I also noticed that the minimum of x^2+2x+3 is 2. Is this relevant?

The expansion on the RHS is too long for thee quadratic case and higher to see any pattern. I don't see how you can deduce anything for Q from that. Can you please elaborate?

Homework Statement Find all the polynomials P(x) for which P(x^2+2x+3)=[P(x+3)]^2 Homework Equations The Attempt at a Solution I don't really know how to solve functional equations systematically. I tried to to find a linear P(x) and found P(x)=x-2 through trial & error. I also tried...