Recent content by TechnocratX

I understand now. I should just have solved the quadratic, then only applied the absolute value +/- to the u function. Thanks for your help.

Solve |x-3|^2 - 4|x-3|=12 The solution to this equation is -3, 9. But I'm not sure on the working. There is a hint to let u=|x-3| So I worked it out the following way. u^2 -4u = 12 u^2 -4u -12 = 0 (u + 2)(u - 6)=0 u /= -2 and u /= 6 |x-3|=-2 (no solution) |x-3|= 6, x = 9 Now to work...

I know this thread is over 8 years old, but this reply is for the benefit of someone like me who stumbles across it. Plus I think I can explain it in a more simpler manner, especially for those with basic stats knowledge. Ok, say you did the first 10,000 coin flips, and got 9000 heads...