Recent content by Teslapb

I submitted the answer of 224.5 and it was correct, I am just not sure why.

So I do not know what that means.

Right, and once you subtract those velocities to find the relative speed it becomes -36-36=72

After relooking at the problem I think that I mistakenly put 36 for i-hat when it would need to be -72 or +72 because the plane needs to match the wind velocity in the opposite direction. For example if the plane x velocity is +36 to cancel the -36 wind velocity it would be 36-(-36)=72. The...

The vector that resulted from the new direction of wind is 72i-hat + 156.74j-hat, which has a magnitude of 172.5km/hr.

My previous answers into my online homework system have been 243, 200, 253.4, and 253.7 km/hr. I believe the last two to be correct. If you can find no other flaw in my work then I think you are correct, the wind is blowing FROM 31 degrees south of east. .

I see what you're saying now. You are right I did not subtract the components of the air velocity twice. I did so once and that is the answer I got in i j format. I then found the magnitude of that vector.

Yes I did that. That was the relative velocity to the air and then the magnitude of that is what I then used as my answer because it is asking for speed not velocity

I found that to be the velocity relative to the air. I then found the magnitude of that vector to me the relative speed.

Homework Statement After flying for 15 min in a wind blowing 42 km/h at an angle of 31° south of east, an airplane pilot is over a town that is 50 km due north of the starting point. What is the speed of the airplane relative to the air? Homework Equations Vx of wind=42km/hr*cos(31) Vy of...