Recent content by The-Steve

I am having troubles understanding how to calculate the current at RSensor when RSensor is 110 Ohms. Any help would be appreciated.

ib = Rin(total)/Rin(base)? Is that correct?

Or the way I drew it. Still no closer to understanding how to calculate Iout though.

r'e = 22.7Ω Rin(base) = 70 * 22.7Ω = 1.59 kΩ Rin(total) = 14.7 kΩ || 1.59 k ohm = 1.43 kΩ Iin = 100mv/1.43kΩ = 69.9 μA Ai = ? / 69.9μA and now I am lost.

Isn't that Il? Isn't Iout the combination of the current through the collector and the load? Iout = Ic + Il?

I am totally confused then on how to calculate current gain. I understand that it's Iout/Iin. I understand how to calculate Iin, but not Iout.

Yes. My mistake. So, if I am following correctly (which I am not sure I am), the current at the base multiplied by the beta AC is equal to the current at the collector. So in my formulas is the current at the base Iin? So is the current at the base Iin = Vin/Rin(total)? And then to find IC...

I need to know if my formula's are correct for current gain. Sorry for shakey drawing. I know beta would change the dc values slightly but for my prof. it's close enough. Beta AC = 70. DC Analysis VB = R1R2/R1+R2 VE = VB - VBE IE = VE/RE AC Analysis r'e = 25mv/IE Req = R1 || R2 Rout = RC ||...