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The biomechanics of elbow extension
𝐹𝑃𝑥 = 93.6650N sin (85 − 90) + 28.11N sin(180 − 85 − 79) Fpx= -8.16344N +7.74816N 𝐹𝑃𝑥 = -0.4154 N←- thegoose
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- Biomechanics Physics Sin
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- Forum: Introductory Physics Homework Help