Recent content by TheGreenMarin

I am going to fail this exam. So I have to consider the whole circuit, right I see. I really need help with electricity.

I think I know where I went wrong. I was following the circuit from left to right, instead of using conventional current flow, so I never actually passed the Z resistor so I excluded it from my calculations. Is that correct?

That makes more sense :D, so I needed to work out the pd across Z first?

Yes, I am confused :confused: The question asks for the current going through Y, so I know the resistance of Y is 3Ω, the pd across Y I worked out as 6V, which is wrong. According to the mark scheme I have to do 10-6 to get 4V, which is the pd across Y, but I don't understand, why did I have...

Yes, I think so, but how would this help me find the current through Y? The mark scheme says I have to take the voltage across Y from the emf to give me 4V then use R = V/I to find the current. I'm still not sure why I have to take the voltage across Y from the emf, why can't I use the...

Homework Statement The problem involves a battery of emf 10V [with no internal resistance] and a combination of resistors. Here is the diagram provided: A picture of the diagram can be found here: http://gyazo.com/7791710d0645de38cfab59f0ac4740ec (Couldn't get the image feature to...

Thank you very much for your help I really appreciate it. I am so glad I found this website, you have helped me greatly. I will definitely stick around here and maybe one day even help people out with their problems (Once I understand the basics). This site is so helpful that I will tell my...

Right OK, I see how you have done that. Is my answer of 20.601 correct?

4.2u = 86.5242 /4.2 = 20.601 ms^-1 Final answer for (a) I think?

Just confused on where the - sign has come from in the line: 0 = 4.2u -(0.5)(9.81)(4.2^2)

0=u x 4.2 + 0.5 x -9.81 x 4.2^2 so 0 = u x -82.3242

-9.81 as its against gravity, rookie error I now got -82.3242 as my answer but I'm not sure how this can be right as it is negative

0=u x 4.2 + 0.5 x 9.81 x 4.2^2 gives me 0 = u x 90.7242 so u = 0 I'm really struggling with this question, what error have I made this time?

Ah, thankyou s now makes sense

0 = v_0 + 9.81x4.2 ? I am not sure I have done this correctly so v_0 = -41.202 <---- I've definitely gone wrong here, the initial speed surely cannot be negative