Recent content by thehippyseal

Thanks for the reply. I seem to have got it right then. With Ia I have 20=3300I_a+6800(I_a-I_c) -15=6800(I_b-I_a )+2200(I_b-I_c) 15=2200(I_c-I_b )+8200(I_c-I_d) -25=8200(I_d-I_c )+4700I_d Cheers.

Homework Statement Using matrix algebra calculate the voltage expected across each resister in the circuit diagram. Only need the simultaneous equations. The Attempt at a Solution -15=6800(I_b-I_a )+2200(I_b-I_c) 15=2200(I_c-I_b )+8200(I_c-I_d) -25=8200(I_d-I_c )+4700I_d Thanks for any help.