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where Vy=Vertical shear force given in the diagram and Ixx =second moment of area calculated as 101.25 x 10^8 mm4, t=thickness and y is the distance to the centroid

i used da formula q=q0 - (Vy/Ixx) Integral t*y*ds and calculated it for qOA, qAB and qBC. qBC = 0 as it lies on the axis of symmetry.

i used da formula q=q0 - (Vy/Ixx) Integral t*y*ds and calculated it for qOA, qAB and qBC. qBC = 0 as it lies on the axis of symmetry.

and sketch the shear flow in the cross section. i am really struggling on this as i don't know how to do it. your help will be much appreciated. thanks

I have got the centroid and the second moment for this problem. and have found the shear flow in the walls. now the question is asking me to evaluate the shear force in the walls. i don't know what that means. can you help please thanks

i mean to find the y distance from the base to the midpoint of the rectangle AB and DE

what i did for rectangle DE and AB: the midpoint will be 0.5m. and then drew a triangle and used sin rule to find the height of centroid vertically. is that right?

I used sin rule to calculate it and it came as 0.866m.

and for the second moment of area i have got 15x10^-3 m^4. can anyone check if that's right please thanks

i have tried doing a solution and the centroid in y-axis is coming as 0.444m. i don't know if that is right or wrong. can you please check it. thanks

but what about the side DE and AB because they are at an angle 120 degree. or do i use sin rule at the centroid of DE to find the height? Thanks

in the question it says find the centroid and second moment of area about the horizontal axis at the centroid. i am confused in the distance of centroid from reference axis for each rectangle, when doing the table. can you please guide me how to do this question. i am using the centroid formula...

Homework Statement To find the centroid and second moment of area of hollow thin walled trapezoidal. Homework Equations The Attempt at a Solution