I think I may have made a little progress.
Loop 1:
When V is Q/C
V = I_{1}R
0 = I_{1}R - V
Loop 2:
V = LdI_{2}/dt
0 = LdI_{2}/dt - V
Combining:
I_{1}R = LdI_{2}/dt
(I'm having a problem with latex it seems, those superscripts are supposed to be subscripts)
Now, this looks...
Homework Statement
Purcell 8.4: In the resonant circuit of the figure(I'll reproduce the image below) the dissipative element is a resistor R' connected in parallel, rather than in series, with the LC combination. Work out the equation analogous to Eq 2. (d^2V/dt^2 + (R/L)(dV/dt) + (1/LC)V = 0...